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5x^2-15+4x^2-2x=180
We move all terms to the left:
5x^2-15+4x^2-2x-(180)=0
We add all the numbers together, and all the variables
9x^2-2x-195=0
a = 9; b = -2; c = -195;
Δ = b2-4ac
Δ = -22-4·9·(-195)
Δ = 7024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7024}=\sqrt{16*439}=\sqrt{16}*\sqrt{439}=4\sqrt{439}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-4\sqrt{439}}{2*9}=\frac{2-4\sqrt{439}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+4\sqrt{439}}{2*9}=\frac{2+4\sqrt{439}}{18} $
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